Activities- Quadratic equations problems

=Ex.no.9.11 /problem no.9= The altitude of a triangle is 6cm greter than its base. If its area is 108cmsq .Find its base. Statement: Solving problem based on quadratic equations. 216=x2+6x x2 +6x -216=0 Substitution: x 2 +18x-12x -216=0 Simplification: x(x+18)-12(x+18)=0 (x+18)( x-12)=0 (x+18)=0 (x-12)=0 x=-18, x=12. =12+6=18cm. Prior Knowledge -
 * Interpretation of the problem: * Converting data in to eqn. *Knowledge about area of a triangle. *knowledge of the formula of area of triangle. *Methods of finding the roots of the eqn. *Methods of finding the roots of the
 * Different approches to solve the problem: *Factorisation
 * Using formula
 * using graph
 * Concept used:Forming the eqn. 216=x(x+6)
 * 1) Base=12cm,  Altitude=x+6
 * Methods of solving the Eqn
 * Factorisation
 * Using Formula
 * Using Graph