Factorisation

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=Additional Information=

Useful websites

 * Question Corner


 * 1) Maths is Fun. This website contains good worksheets for factorisation.
 * 2) Wolfram Mathworld. This website contains good simulations for math identities.

NCERT Books

 * 1) Algebraic expressions and identities
 * 2) Factorisation

= Teaching Outlines =

Learning objectives
To introduce expressions and the need and method of splitting

Activities
http://www.infomontessori.com/sensorial/montessori_binomial_cube_1.jpg
 * 1) Activity #1
 * 2) Activity #2 Demonstrate Binomial Cube

Activity No #1 Geogebra
This is a Geogebra screenshot for identity. This is a classroom demonstration of binomial cube. Show the children before you start the cubic identity.
 * Estimated Time
 * Materials/ Resources needed
 * Prerequisites/Instructions, if any
 * Multimedia resources
 * Website interactives/ links/ / Geogebra Applets
 * Process/ Developmental Questions
 * Evaluation
 * Question Corner

Activity No #

 * Estimated Time
 * Materials/ Resources needed
 * Prerequisites/Instructions, if any
 * Multimedia resources
 * Website interactives/ links/ / Geogebra Applets
 * Process/ Developmental Questions
 * Evaluation
 * Question Corner

Question : If x= and y= find
 * 1) = Hints for difficult problems =

Solution :

Analysing the given condition

Step 1 : =  => Using the formula : =

step 2 : = ( + )(-) => substitute the value of x and  y

Step 3 : = x => take the L.C.M of the denominator, simplyfy using concept of addition and substaction of fraction

Step 4: = x simply the above using basic concepts of addition and substraction

Step 5 : = x

Step 6 := x => take common term 2 ( H.C.F)

Step 7 : = x

Step 8 : = =hints for difficult problem=

If x-= 4   prove that $$x^{3}+6x^{2}+\frac {6}  {x^{2}}-\frac{1}  {x^{3}}=184  $$

=
If x+y=a  and xy=b then prove that                                          (1+)+(1+) =

Steps for solution

step 1: * Understanding the  problem first. * Recalling the indentities step 2 :  * consider the condition and squaring on both side * simplify to get the value step 3:   *  consider  LHS * multiply the expression * substitute the value * simlpify the equqtion

solution for the problem

consider x+y=a = substitute x+y =a and xy=b then we get --->(1) consider xy=b squaring on both side then we get =--->(2)

consider LHS= =(1+)+(1+)		=1+		= 1+ from eqn 1 & 2 =		=        LHS = RHS=============

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