Activities-Pythagoras theorem problems

From Karnataka Open Educational Resources
Jump to: navigation, search

Difficulty problems in Exercise 11.1 in pythagorus theorem chapter'


(4) In Right angled ∆ABC,∟BAC= 90°,∟B: ∟C = 1:2 andAC= 4cm.calculate thelenght of BC

'Solution

in some special right angled triangle

whose angle ratio 1:2:3 that is 30-60-90

has their sides ratio 1:  :2

in ▲ABC, BC = 2. AC

BC = 2.4

BC = 8 cm


(6) A door of width 6 mt has an archabove it having aheight of 2 mt , find the radius if the arch


Solution

In figure given AB=6 mt width of door CD=2 mt height of arch let OC is radius of arch OD= x mt jion OB, in ∆ODB ∟D= 90º

4x=9-4

x=

x=1.25

But OC = 2+x

   OC= 2+1.25
   OC= 3.25 mt

radius of arch is 3.25 mt


(7) The sides of a right angled triangle are in an AP. Show that sides are in ther ratio 3:4:5

Solution

IN right angled triangle ABC If ∟B=90º and sides are in AP

Let AB= a-d

   BC= a
   AC= a+d

then

a=4d

AB=a-d=4d-d=3d

BC= a=4d

AC= a+d+ 4d+d =5d

ratio of sides is 3d:4d:5d

if sides of the right angled triangle are in ratio 3:4:5 then their sides are in AP