Line 41: |
Line 41: |
| |10 | | |10 |
| |08 | | |08 |
| + | |} |
| + | |
| + | =INTERPRETATION OF PROBLEM= |
| + | |
| + | =Previous knowledge= |
| + | |
| + | =Solution:= |
| + | {|class="wikitable" |
| + | |- |
| + | |x |
| + | |f |
| + | |fx |
| + | |x² |
| + | |fx² |
| + | |- |
| + | |03 |
| + | |07 |
| + | |021 |
| + | |009 |
| + | |0063 |
| + | |- |
| + | |08 |
| + | |10 |
| + | |080 |
| + | |064 |
| + | |0640 |
| + | |- |
| + | |13 |
| + | |15 |
| + | |195 |
| + | |169 |
| + | |2535 |
| + | |- |
| + | |18 |
| + | |10 |
| + | |180 |
| + | |324 |
| + | |3240 |
| + | |- |
| + | |23 |
| + | |08 |
| + | |184 |
| + | |529 |
| + | |4232 |
| + | |- |
| + | | |
| + | |n=50 |
| + | |Σfx=660 |
| + | | |
| + | |Σfx²=10710 |
| + | |} |
| + | |
| + | |
| + | |
| + | Standard deviation σ=<math>\sqrt{\frac {\sum {fx^2}}{n}-({\frac{\sum fx}{n})^2}}</math> <br> |
| + | σ=<math>\sqrt{\frac{10700}{50}-({\frac{660}{50})^2}}</math> <br> |
| + | σ=<math>\sqrt{214-174.24}</math> <br> |
| + | σ=<math>\sqrt{39.96}</math> <br> |
| + | σ=6.3 |
| + | |
| + | =Problem 3= |
| + | Problem No.5 of excercise No.6.3 <br> |
| + | Find the varience and Standard deviation for the following data. |
| + | {|class="wikitable" |
| + | |- |
| + | |class intervals |
| + | |30-34 |
| + | |34-38 |
| + | |38-42 |
| + | |42-46 |
| + | |46-50 |
| + | |50-54 |
| + | |- |
| + | |f |
| + | |04 |
| + | |07 |
| + | |09 |
| + | |11 |
| + | |06 |
| + | |03 |
| |} | | |} |
| | | |