Changes
From Karnataka Open Educational Resources
21 bytes added
, 07:26, 14 August 2014
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| c=4<br> | | c=4<br> |
| d=<math>\frac{x-A}{c}</math>=<math>\frac{32-40}{4}</math>=<math>\frac{-8}{4}=-2</math><br> | | d=<math>\frac{x-A}{c}</math>=<math>\frac{32-40}{4}</math>=<math>\frac{-8}{4}=-2</math><br> |
| + | |
| assumed mean A=<math>\frac{\sum fx}{n}</math>=<math>\frac{1668}{40}=41.7</math><br> | | assumed mean A=<math>\frac{\sum fx}{n}</math>=<math>\frac{1668}{40}=41.7</math><br> |
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| σ²=[<math>\frac{85}{40}-({\frac{17}{40})^2}]4^2</math> <br> | | σ²=[<math>\frac{85}{40}-({\frac{17}{40})^2}]4^2</math> <br> |
| | | |
− | σ²=[<math>\2.125-0.180]16</math> <br> | + | σ²=[2.125-0.180]16<br> |
| + | |
| + | σ²=[1.945]16<br> |
| | | |
| + | σ²=31.12<br> |
| Standard deviation σ=<math>\sqrt{\frac {\sum {fx^2}}{n}-({\frac{\sum fx}{n})^2}}</math> <br> | | Standard deviation σ=<math>\sqrt{\frac {\sum {fx^2}}{n}-({\frac{\sum fx}{n})^2}}</math> <br> |
| σ=<math>\sqrt{\frac{10700}{50}-({\frac{660}{50})^2}}</math> <br> | | σ=<math>\sqrt{\frac{10700}{50}-({\frac{660}{50})^2}}</math> <br> |