Anonymous

Changes

From Karnataka Open Educational Resources
Line 205: Line 205:  
c=4<br>
 
c=4<br>
 
d=<math>\frac{x-A}{c}</math>=<math>\frac{32-40}{4}</math>=<math>\frac{-8}{4}=-2</math><br>
 
d=<math>\frac{x-A}{c}</math>=<math>\frac{32-40}{4}</math>=<math>\frac{-8}{4}=-2</math><br>
 +
 
assumed mean A=<math>\frac{\sum fx}{n}</math>=<math>\frac{1668}{40}=41.7</math><br>
 
assumed mean A=<math>\frac{\sum fx}{n}</math>=<math>\frac{1668}{40}=41.7</math><br>
   Line 211: Line 212:  
σ²=[<math>\frac{85}{40}-({\frac{17}{40})^2}]4^2</math> <br>
 
σ²=[<math>\frac{85}{40}-({\frac{17}{40})^2}]4^2</math> <br>
   −
σ²=[<math>\2.125-0.180]16</math> <br>
+
σ²=[2.125-0.180]16<br>
 +
 
 +
σ²=[1.945]16<br>
    +
σ²=31.12<br>
 
Standard deviation σ=<math>\sqrt{\frac {\sum {fx^2}}{n}-({\frac{\sum fx}{n})^2}}</math> <br>
 
Standard deviation σ=<math>\sqrt{\frac {\sum {fx^2}}{n}-({\frac{\sum fx}{n})^2}}</math> <br>
 
σ=<math>\sqrt{\frac{10700}{50}-({\frac{660}{50})^2}}</math> <br>
 
σ=<math>\sqrt{\frac{10700}{50}-({\frac{660}{50})^2}}</math> <br>
45

edits