1,122
edits
Changes
From Karnataka Open Educational Resources
Activities - progressions problems (view source)
Revision as of 04:00, 30 October 2019
, 04:00, 30 October 2019added Category:Progressions using HotCat
a + b – 10b = 0<br>
a + b – 10b = 0<br>
a – 9b = 0<br>
a – 9b = 0<br>
a = 9b<br>
Consider equation 1<br>
Consider equation 1<br>
a + b = 2 (<math>\sqrt{ab}</math> + 2 )<br>
a + b = 2 (<math>\sqrt{ab}</math> + 2 )<br>
a + 1 = 10<br>
a + 1 = 10<br>
a = 10-1<br>
a = 10-1<br>
a = 9
a = 9<br>
=Problem 4=
=Problem 4=
''' Exercise 3.7 , Problem number 10, Page number 62 '''
''' Exercise 3.7 , Problem number 10, Page number 62 '''
2ab = <math>b^{2}</math> + bc ---------->1<br>
2ab = <math>b^{2}</math> + bc ---------->1<br>
Also 'b' is the geometric mean between 'a' and 'c'<br>
Also 'b' is the geometric mean between 'a' and 'c'<br>
That is b = <math>\sqrt{ac}</math><br> ------------------> 2<br>
That is b = <math>\sqrt{ac}</math><br>
We also write this as <math>b^{2}</math> = ac.-------->2<br>
Now substitute thia value In equation 1,<br>
2ab = ac + bc<br>
Take common in right hand side ( c is common )<br>
2ab = c(a + b)<br>
Divide both side by (a + b),<br>
<math>\frac{2ab} {a + b}</math>= c<br>
Hence 'c' is the harmonic between 'a' and 'b'.
[[Category:Progressions]]
