Changes
From Karnataka Open Educational Resources
526 bytes added
, 04:24, 30 October 2019
mLine 2: |
Line 2: |
| The altitude of a triangle is 6cm greter than its base. If its area is 108cmsq .Find its base.<br> | | The altitude of a triangle is 6cm greter than its base. If its area is 108cmsq .Find its base.<br> |
| Statement: Solving problem based on quadratic equations.<br> | | Statement: Solving problem based on quadratic equations.<br> |
− | *Interpretation<br>retation of the problem:<br> * Converting data in to eqn.<br> *Knowledge about area of a triangle.<br>*knowledge of the formula of area of triangle.<br>*Methods of finding the roots of the eqn.<br> | + | *Interpretation of the problem:<br> * Converting data in to eqn.<br> *Knowledge about area of a triangle.<br>*knowledge of the formula of area of triangle.<br>*Methods of finding the roots of the eqn.<br> *Methods of finding the roots of the |
| + | *Different approches to solve the problem: <br>*Factorisation |
| + | *Using formula |
| + | *using graph |
| + | *Concept used:Forming the eqn. 216=x(x+6) |
| + | 216=x2+6x<br> |
| + | x2 +6x -216=0<br> |
| + | Substitution: x 2 +18x-12x -216=0<br> |
| + | Simplification: x(x+18)-12(x+18)=0<br> |
| + | (x+18)( x-12)=0<br> |
| + | (x+18)=0 (x-12)=0<br> |
| + | x=-18, x=12<br>. |
| + | # Base=12cm, <br> Altitude=x+6 |
| + | =12+6=18cm.<br> |
| + | '''Prior Knowledge''' -<br> |
| + | *Methods of solving the Eqn<br> |
| + | *Factorisation<br> |
| + | *Using Formula<br> |
| + | *Using Graph<br> |
| + | |
| + | [[Category:Quadratic Equations]] |