Difference between revisions of "Quadrilaterals-Activity-Mid-point theorem"
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=== Objectives === | === Objectives === | ||
− | # | + | # To guide and facilitate student exploration of the properties of triangles, specifically – a segment connecting mid-points of two sides of a triangle will be parallel to the third side and its length will be half of the third side. |
− | # | + | # To introduce theorems associated with triangles |
+ | # To demonstrate the steps of logical proof and the processes | ||
+ | # Understand properties of triangles | ||
=== Estimated Time === | === Estimated Time === | ||
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=== Prerequisites/Instructions, prior preparations, if any === | === Prerequisites/Instructions, prior preparations, if any === | ||
− | + | An understanding of the basic elements of geometry. Students are familiar with angles and parallel lines, and have been introduced to the concepts of parallelogram | |
=== Materials/ Resources needed === | === Materials/ Resources needed === | ||
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Work sheet | Work sheet | ||
− | Each group member will construct on her / his notebook, using pencil, scale, protractor, and compass a triangle, with the measures provided | + | Each group member will construct on her / his notebook, using pencil, scale, protractor, and compass a triangle, with the measures provided. You can make chits that have triangle measures. You can even repeat them. For a group give the following. One acute. One obtuse. One equilateral. One isosceles. One right. Provide only measures, for e.g. |
+ | # Draw a triangle with following measures - BC = 6 cms, AC = 7 cms, AB = 8 cms (BC as the base) | ||
+ | # Draw a triangle with following measures BC = 8 cms, angle B = 110, AB = 6 cms (BC as the base) | ||
+ | # Draw a triangle with following measures BC = 10 cms, angle B = 60, angle C = 60 (BC as the base) | ||
+ | # Draw a triangle with following measures BC = 12 cms, angle B = 90, AC = 13 cms (BC as the base) | ||
+ | # Draw a triangle with following measures BC = 8 cms, angle B = 40, angle C = 40 (BC as the base) | ||
+ | # Draw a triangle with following measures BC = 6 cms, angle B = 110, AB = 5 cms (BC as the base) | ||
+ | # Draw a triangle with following measures BC = 8 cms, angle B = 60, angle C = 40 (BC as the base) | ||
− | # Students should plot the mid-point of two sides and connect these with a line segment. Show [[:File:Mid-point theorem 1.ggb|Mid-point theorem1.ggb]] step by step. | + | Each group gets this set and each member picks one chit and makes a sketch |
+ | # Students should plot the mid-point of two sides (Segment AB, and AC, as D and E) and connect these with a line segment (Join these mid-points D and E. Label it Segment DE). Show [[:File:Mid-point theorem 1.ggb|Mid-point theorem1.ggb]] step by step. | ||
## They should measure the length of this segment and length of the third side and check if there is any relationship | ## They should measure the length of this segment and length of the third side and check if there is any relationship | ||
## They should measure the angles formed at the two vertices connecting the third side, with the two angles formed on the two mid-points | ## They should measure the angles formed at the two vertices connecting the third side, with the two angles formed on the two mid-points |
Revision as of 18:13, 7 November 2019
Objectives
- To guide and facilitate student exploration of the properties of triangles, specifically – a segment connecting mid-points of two sides of a triangle will be parallel to the third side and its length will be half of the third side.
- To introduce theorems associated with triangles
- To demonstrate the steps of logical proof and the processes
- Understand properties of triangles
Estimated Time
One period
Prerequisites/Instructions, prior preparations, if any
An understanding of the basic elements of geometry. Students are familiar with angles and parallel lines, and have been introduced to the concepts of parallelogram
Materials/ Resources needed
Digital - Computer, Geogebra application, projector. Geogebra files- Mid-point theorem1.ggb and Mid-point theorem2.ggb
Non digital - worksheet and pencil.
Process (How to do the activity)
Work sheet
Each group member will construct on her / his notebook, using pencil, scale, protractor, and compass a triangle, with the measures provided. You can make chits that have triangle measures. You can even repeat them. For a group give the following. One acute. One obtuse. One equilateral. One isosceles. One right. Provide only measures, for e.g.
- Draw a triangle with following measures - BC = 6 cms, AC = 7 cms, AB = 8 cms (BC as the base)
- Draw a triangle with following measures BC = 8 cms, angle B = 110, AB = 6 cms (BC as the base)
- Draw a triangle with following measures BC = 10 cms, angle B = 60, angle C = 60 (BC as the base)
- Draw a triangle with following measures BC = 12 cms, angle B = 90, AC = 13 cms (BC as the base)
- Draw a triangle with following measures BC = 8 cms, angle B = 40, angle C = 40 (BC as the base)
- Draw a triangle with following measures BC = 6 cms, angle B = 110, AB = 5 cms (BC as the base)
- Draw a triangle with following measures BC = 8 cms, angle B = 60, angle C = 40 (BC as the base)
Each group gets this set and each member picks one chit and makes a sketch
- Students should plot the mid-point of two sides (Segment AB, and AC, as D and E) and connect these with a line segment (Join these mid-points D and E. Label it Segment DE). Show Mid-point theorem1.ggb step by step.
- They should measure the length of this segment and length of the third side and check if there is any relationship
- They should measure the angles formed at the two vertices connecting the third side, with the two angles formed on the two mid-points
- Question them if there is any relationship between the two segment lengths and the measures of the two pairs of angles.
- Ask them why these relationships are true across different constructions.
- Prove the theorem, using Mid-point theorem2.ggb
- In △ ABC, D and E are the midpoints of sides AB and AC respectively. D and E are joined.
- Given: AD = DB and AE = EC. To Prove: DE ∥∥ BC and DE = 1/2 BC.
- Construction: Extend line segment DE to F such that DE = EF. Draw segment CF.
- Proof: In △ ADE and △ CFE AE = EC (given)
- ∠AED = ∠CEF (vertically opposite angles)
- DE = EF (construction)
- Hence △ ADE ≅ △ CFE by SAS congruence rule.
- Therefore, ∠ADE = ∠CFE (by CPCT) and ∠DAE = ∠FCE (by CPCT) AD = CF (by CPCT).
- ∠ADE and ∠CFE are alternate interior angles,
- (AB and CF are 2 lines intersected by transversal DF).
- ∠DAE and ∠FCE are alternate interior angles,
- (AB and CF are 2 lines intersected by transversal AC).
- Therefore, AB ∥∥ CF. So - BD ∥∥ CF.
- BD = CF (since AD = BD and it is proved above that AD = CF).
- Thus, BDFC is a parallelogram.
- By the properties of parallelogram, we have DF ∥∥ BC DF = BC DE ∥∥ BC.
- DE = 1/2BC (DE = EF by construction)
Evaluation at the end of the activity
- Would this theorem apply for right angled and obtuse-angled triangles?