Difference between revisions of "Activity- statistics problems"

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=Problem 1=
 
=Problem 1=
If n =10, ,math.\\bar x</math> =  12 and
+
If n =10, <math>\bar x </math> =  12 and<br>
<math>\sum{x^2}= 1530  find the standard deviation </math> <br>
+
<math>\sum{x^2}= 1530  find the standard deviation </math> <br>
  
 
=INTERPRETATION OF PROBLEM=
 
=INTERPRETATION OF PROBLEM=
Line 218: Line 218:
 
σ²=31.12<br>
 
σ²=31.12<br>
 
standard deviation, σ=<math>\sqrt{varience}</math> <br>  
 
standard deviation, σ=<math>\sqrt{varience}</math> <br>  
σ=<math>\sqrt{31.12}</math> <br>
+
σ=<math>\sqrt{31.12}</math> <br>
σ=5.58
+
σ=5.58
 +
 
 +
[[Category:Statistics]]

Latest revision as of 09:56, 30 October 2019

Problem 1

If n =10, = 12 and

INTERPRETATION OF PROBLEM

Previous knowledge

Solution:





σ=
σ=
σ=
σ=
σ=
σ=3

Problem 2

Problem No.1 of excercise No.6.1
Find the Standard deviation for the following data.

x 03 08 13 18 23
f 07 10 15 10 08

INTERPRETATION OF PROBLEM

Previous knowledge

Solution:

x f fx fx²
03 07 021 009 0063
08 10 080 064 0640
13 15 195 169 2535
18 10 180 324 3240
23 08 184 529 4232
n=50 Σfx=660 Σfx²=10710


Standard deviation σ=
σ=
σ=
σ=
σ=6.3

Problem 3

Problem No.5 of excercise No.6.3
Find the varience and Standard deviation for the following data.

class intervals(CI) 30-34 34-38 38-42 42-46 46-50 50-54
freequency(f) 04 07 09 11 06 03

INTERPRETATION OF PROBLEM

Previous knowledge

Solution:

C.I. f x fx d= fd fd²
30-34 4 32 128 -2 -8 4 16
34-38 7 36 252 -1 -7 1 7
38-42 9 40 360 0 0 0 0
42-46 11 44 484 1 11 1 11
46-50 6 48 288 2 12 4 24
50-54 3 52 156 3 9 9 27
n=40 Σfx=1668 Σfd=17 Σfd²=85

A=assumed average.
c=4
d===

assumed mean A==

Varience σ²=[

σ²=[

σ²=[2.125-0.180]16

σ²=[1.945]16

σ²=31.12
standard deviation, σ=
σ=
σ=5.58