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From Karnataka Open Educational Resources
→Hints for difficult problems
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=8-3<br>
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=Ex.no.9.11 /problem no.9=
The altitude of a triangle is 6cm greter than its base. If its area is 108cmsq .Find its base.<br>
Statement: Solving problem based on quadratic equations.<br>
*Interpretation of the problem:<br> * Converting data in to eqn.<br> *Knowledge about area of a triangle.<br>*knowledge of the formula of area of triangle.<br>*Methods of finding the roots of the eqn.<br> *Methods of finding the roots of the
*Different approches to solve the problem: <br>*Factorisation
*Using formula
*using graph
*Concept used:Forming the eqn. 216=x(x+6)
216=x2+6x<br>
x2 +6x -216=0<br>
Substitution: x 2 +18x-12x -216=0<br>
Simplification: x(x+18)-12(x+18)=0<br>
(x+18)( x-12)=0<br>
(x+18)=0 (x-12)=0<br>
x=-18, x=12<br>.
# Base=12cm, <br> Altitude=x+6
=12+6=18cm.<br>
'''Prior Knowledge''' -<br>
*Methods of solving the Eqn<br>
*Factorisation<br>
*Using Formula<br>
*Using Graph<br>
= Project Ideas =
= Project Ideas =
= Math Fun =
= Math Fun =
