Changes
From Karnataka Open Educational Resources
34 bytes added
, 05:16, 4 September 2013
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| <math>{\pi}=\frac{3}{4}{\sqrt{3}}+24{\int_0^{1/4}}{\sqrt{x-x^2}dx}</math> | | <math>{\pi}=\frac{3}{4}{\sqrt{3}}+24{\int_0^{1/4}}{\sqrt{x-x^2}dx}</math> |
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| + | <math>\sqrt{3x-1}+(1+x)^2</math> |