Difference between revisions of "Activities-Real numbers"
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Pupil can solve this in several ways viz., proofs by cases. | Pupil can solve this in several ways viz., proofs by cases. | ||
===Case -1: x is an even integer === | ===Case -1: x is an even integer === | ||
+ | Then x=2k+0 = 2K, K<math>K in Z </math> by Euclid's lemma<br> | ||
+ | |||
+ | Discussion on Euclid's lemma: What is division? Discuss on the process of division rather than on the procedure of division. Consider the example . Is it (12-5)=7 then (7-5)=2 |
Revision as of 10:52, 10 July 2014
Problem 1
- For every integer prove that x(x+1) is an even integer (Problem related to mathematical proofs in Chapter 1)
Approaches to solutions
The concepts that a pupil must know are
- What is an integer?
- What is an even integer?
- What is an odd integer?
- X and ( x+1) are consecutive integers and x(x+1) is the representation of the product
- Pupil should have the concept of distributive property of integers
- The pupil must have an opportunity for an arguement that the proof is true even of negative integers
- Pupil must have a sound understanding of Euclid's lemma
- The difference between mathematical proofs and Verification/Justification-the scope of mathematical proofs is beyond verification-Higher order skill in problem solving
Method -1: Solution by cases
Proposition: x is an integer. i.e., x=m, where m is an integer
Conclusion : x(x+1) is an even integer. i.e., x(x+1) =2K
Pupil can solve this in several ways viz., proofs by cases.
Case -1: x is an even integer
Then x=2k+0 = 2K, K by Euclid's lemma
Discussion on Euclid's lemma: What is division? Discuss on the process of division rather than on the procedure of division. Consider the example . Is it (12-5)=7 then (7-5)=2