Difference between revisions of "Progressions"
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Please click[http://karnatakaeducation.org.in/KOER/en/index.php/Class10_progressions_problems here\] here for the solution. | Please click[http://karnatakaeducation.org.in/KOER/en/index.php/Class10_progressions_problems here\] here for the solution. | ||
#In an arithmatic progression if the first term is 'a' , second term is 'b' and last term is 'c' then prove that sum is equal to | #In an arithmatic progression if the first term is 'a' , second term is 'b' and last term is 'c' then prove that sum is equal to | ||
| − | {((a+c)*(b+c-2*a))} over {(2*(b-a))} | + | <math>{\((a+c)*(b+c-2*a))} over {(2*(b-a))}</math> |
= Project Ideas = | = Project Ideas = | ||
Revision as of 11:06, 11 July 2014
| Philosophy of Mathematics |
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Hints for difficult problems
- A company employed 400 persons in the year 2001 and each year increased by 35 persons. In which year the number of employees in the company will be 785?
Please clickhere\ here for the solution.
- In an A.P. sum of first 6 terms is 345.If difference between first term and last term is 55 then find that terms.
Please clickhere\ here for the solution.
- In an arithmatic progression if the first term is 'a' , second term is 'b' and last term is 'c' then prove that sum is equal to
Failed to parse (syntax error): {\displaystyle {\((a+c)*(b+c-2*a))} over {(2*(b-a))}}
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