Difference between revisions of "Activity-trigonometry problems"

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Line 16: Line 16:
 
# '''Generalisation By Verification'''
 
# '''Generalisation By Verification'''
 
   When A=60°
 
   When A=60°
LHS=<math>\frac{1-\tan^2 60°}{1+\tan^2 60°}</math> <br>
+
LHS=<math>\frac{1-\tan^2 60°}{1+\tan^2 60°}</math> <br>=<math>\frac{1-{(\sqrt{3})}^2 }{1+{(\sqrt{3})}^2 }</math>

Revision as of 23:11, 31 July 2014

Problem-1

prove that

Interpretation of problems

  1. It is to prove the problem based on trigonometric identities
  2. the function of one trigonometric ratio is relates to other

Concept development

Develop the skill of proving problem based trigonometric identity

Skill development

Problem solving

Pre Knowledge require

  1. Idea about trignometric ratios
  2. Idea about trignometric identities

Methos

  1. Generalisation By Verification
 When A=60°

LHS=Failed to parse (syntax error): {\displaystyle \frac{1-\tan^2 60°}{1+\tan^2 60°}}
=