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From Karnataka Open Educational Resources
→Activity No #
There are 'n' angles in a polygon of side 'n'.Out of 'n' angles 2 angles are right anles and other (n-2) angles are each.
There are 'n' angles in a polygon of side 'n'.Out of 'n' angles 2 angles are right anles and other (n-2) angles are each.
(2n-4) <math>90^0</math> = (n-2)<math>\144^0+{2}{90}^0</math>Students know how to open the bracket and substitute the values)
(2n-4) <math>90^0</math> = (n-2)<math>\144^0+(2)(90^0)how to open the bracket and substitute the values)
2n x - 4 x =
2n x - 4 x =
