Difference between revisions of "Activities-Pythagoras theorem problems"
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ganeshmath (talk | contribs) (Created page with "#In Right angled ∆ABC,∟BAC= 90°,∟B: ∟C = 1:2 andAC= 4cm.calculate thelenght of BC #A door of width 6 mt has an archabove it having aheight of 2 mt , find the radius i...") |
Venkatesh VT (talk | contribs) |
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#In Right angled ∆ABC,∟BAC= 90°,∟B: ∟C = 1:2 andAC= 4cm.calculate thelenght of BC | #In Right angled ∆ABC,∟BAC= 90°,∟B: ∟C = 1:2 andAC= 4cm.calculate thelenght of BC | ||
| + | ''''''Solution''''''''' | ||
| + | in some special right angled triangle | ||
| + | whose angle ratio 1:2:3 that is 30-60-90 | ||
| + | has their sides ratio 1: <math>{\sqrt3}</math> :2 | ||
| + | |||
| + | in ▲ABC, | ||
| + | BC = 2. AC | ||
| + | |||
| + | BC = 2.4 | ||
| + | |||
| + | BC = 8 cm | ||
| + | |||
#A door of width 6 mt has an archabove it having aheight of 2 mt , find the radius if the arch | #A door of width 6 mt has an archabove it having aheight of 2 mt , find the radius if the arch | ||
# The sides of a right angled triangle are in an AP. Show that sides are in ther ratio 3:4:5 | # The sides of a right angled triangle are in an AP. Show that sides are in ther ratio 3:4:5 | ||
Revision as of 05:58, 11 July 2014
- In Right angled ∆ABC,∟BAC= 90°,∟B: ∟C = 1:2 andAC= 4cm.calculate thelenght of BC
'Solution'''' in some special right angled triangle
whose angle ratio 1:2:3 that is 30-60-90
has their sides ratio 1: :2
in ▲ABC, BC = 2. AC
BC = 2.4
BC = 8 cm
- A door of width 6 mt has an archabove it having aheight of 2 mt , find the radius if the arch
- The sides of a right angled triangle are in an AP. Show that sides are in ther ratio 3:4:5