Revision as of 17:41, 31 July 2014

Problem-1

prove that ${\frac {1-\tan ^{2}A}{1+\tan ^{2}A}}=1-\sin ^{2}A$

Interpretation of problems

It is to prove the problem based on trigonometric identities
the function of one trigonometric ratio is relates to other

Concept development

Develop the skill of proving problem based trigonometric identity

Skill development

Problem solving

Pre Knowledge require

Idea about trignometric ratios
Idea about trignometric identities

Methos

Generalisation By Verification

 When A=60°

LHS=Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \frac{1-\tan^2 60°}{1+\tan^2 60°}}
= ${\frac {1-{({\sqrt {3}})}^{2}}{1+{({\sqrt {3}})}^{2}}}$

@@ Line 16: / Line 16: @@
 # '''Generalisation By Verification'''
    When A=60°
-LHS=<math>\frac{1-\tan^2 60°}{1+\tan^2 60°}</math> <br>
+LHS=<math>\frac{1-\tan^2 60°}{1+\tan^2 60°}</math> <br>=<math>\frac{1-{(\sqrt{3})}^2 }{1+{(\sqrt{3})}^2 }</math>

Difference between revisions of "Activity-trigonometry problems"