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By axiom-1, AQ=BQ<br>
 
By axiom-1, AQ=BQ<br>
 
∴tangent at P bisects AB at Q.
 
∴tangent at P bisects AB at Q.
 +
 
=problem 3 [Ex-15.2 B.7]=
 
=problem 3 [Ex-15.2 B.7]=
 
Circles  <math>C_{1}</math>  and  <math>C_{2}</math>  touch internally at a point  A and AB is a chord of the circle<math>C_{1}</math>    intersecting  <math>C_{2}</math>  at P, Prove that  AP= PB.<br>
 
Circles  <math>C_{1}</math>  and  <math>C_{2}</math>  touch internally at a point  A and AB is a chord of the circle<math>C_{1}</math>    intersecting  <math>C_{2}</math>  at P, Prove that  AP= PB.<br>

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