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added Category:Algebraic expressions using HotCat
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''[http://karnatakaeducation.org.in/KOER/index.php/ಅಪವರ್ತಿಸುವಿಕೆ ಕನ್ನಡದಲ್ಲಿ ನೋಡಿ]''</div>
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[http://www.karnatakaeducation.org.in/KOER/en/index.php/Mathematics:_History The Story of Mathematics]
[http://karnatakaeducation.org.in/KOER/en/index.php/Mathematics:_History The Story of Mathematics]
|style=" width:10%; border:none; border-radius:5px;box-shadow: 10px 10px 10px #888888; background:#f9f9ff; vertical-align:middle; text-align:center; "|[http://www.karnatakaeducation.org.in/KOER/en/index.php/Mathematics:_Philosophy Philosophy of Mathematics]
|style=" width:10%; border:none; border-radius:5px;box-shadow: 10px 10px 10px #888888; background:#f9f9ff; vertical-align:middle; text-align:center; "|[http://karnatakaeducation.org.in/KOER/en/index.php/Mathematics:_Philosophy Philosophy of Mathematics]
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[http://www.karnatakaeducation.org.in/KOER/en/index.php/Mathematics:_Pedagogy Teaching of Mathematics]
[http://karnatakaeducation.org.in/KOER/en/index.php/Mathematics:_Pedagogy Teaching of Mathematics]
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[http://www.karnatakaeducation.org.in/KOER/en/index.php/Maths:_Curriculum_and_Syllabus Curriculum and Syllabus]
[http://karnatakaeducation.org.in/KOER/en/index.php/Maths:_Curriculum_and_Syllabus Curriculum and Syllabus]
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[http://www.karnatakaeducation.org.in/KOER/en/index.php/Mathematics:_Topics Topics in School Mathematics]
[http://karnatakaeducation.org.in/KOER/en/index.php/Mathematics:_Topics Topics in School Mathematics]
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[http://www.karnatakaeducation.org.in/KOER/en/index.php/Text_Books#Mathematics_-_Textbooks Textbooks]
[http://karnatakaeducation.org.in/KOER/en/index.php/Text_Books#Mathematics_-_Textbooks Textbooks]
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[http://www.karnatakaeducation.org.in/KOER/en/index.php/Maths:_Question_Papers Question Bank]
[http://karnatakaeducation.org.in/KOER/en/index.php/Maths:_Question_Papers Question Bank]
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= Concept Map =
= Concept Map =
[[File:Factorisation.mm|Flash]]
= Textbook =
= Textbook =
=Additional Information=
=Additional Information=
{{#widget:YouTube|id=LitM6ERl88A}}
==Useful websites==
==Useful websites==
*Question Corner
#[http://www.mathsisfun.com/algebra/polynomials.html Maths is Fun]. This website contains good worksheets for factorisation.
#[http://www.mathsisfun.com/algebra/polynomials.html Maths is Fun]. This website contains good worksheets for factorisation.
#[http://reference.wolfram.com/mathematica/guide/PolynomialAlgebra.html Wolfram Mathworld]. This website contains good simulations for math identities.
#[http://reference.wolfram.com/mathematica/guide/PolynomialAlgebra.html Wolfram Mathworld]. This website contains good simulations for math identities.
To introduce expressions and the need and method of splitting
To introduce expressions and the need and method of splitting
===Notes for teachers===
===Notes for teachers===
===Activity No # ===
===Activities===
#Activity #1
#Activity #2 Demonstrate Binomial Cube
http://www.infomontessori.com/sensorial/montessori_binomial_cube_1.jpg
http://www.infomontessori.com/sensorial/montessori_binomial_cube_1.jpg
==Concept #==
==Concept #==
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*Estimated Time
*Estimated Time
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*Estimated Time
*Estimated Time
= Hints for difficult problems =
# = Hints for difficult problems =
Question : If x= and y= find
Solution :
Analysing the given condition
Step 1 : = ()() => Using the formula : = ( )()
step 2 : = ( + )(-) => substitute the value of x and y
Step 3 : = x => take the L.C.M of the denominator , simplyfy using concept of addition and substaction of fraction
Step 4: = x
simply the above using basic concepts of addition and substraction
Step 5 : = x
Step 6 := x => take common term 2 ( H.C.F)
Step 7 : = x
Step 8 : =
#
=hints for difficult problem=
If x-= 4 prove that <math>x^{3}+6x^{2}+\frac {6} {x^{2}}-\frac{1} {x^{3}}=184 </math>
=====If x+y=a and xy=b then prove that (1+)+(1+) =
Steps for solution
step 1: * Understanding the problem first.
* Recalling the indentities
step 2 : * consider the condition and squaring on both side
* simplify to get the value
step 3: * consider LHS
* multiply the expression
* substitute the value
* simlpify the equqtion
solution for the problem
consider x+y=a
=
substitute x+y =a and xy=b
then we get
------->(1)
consider xy=b squaring on both side
then we get =------->(2)
consider LHS=
=(1+)+(1+)
=1+
= 1+ from eqn 1 & 2
=
=
LHS = RHS=============
= Project Ideas =
= Project Ideas =
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[[Category:Class 8]]
[[Category:Algebraic expressions]]