Changes

Jump to navigation Jump to search
1,391 bytes added ,  06:57, 8 January 2013
Line 41: Line 41:  
1. When we combine Algebra and Geometry - this feature is not as good in CaRMetal.
 
1. When we combine Algebra and Geometry - this feature is not as good in CaRMetal.
 
2. When we combine statistics (spreadsheets) ,  with algebra, charts - Geometry - this feature is not there in CaRMetal.
 
2. When we combine statistics (spreadsheets) ,  with algebra, charts - Geometry - this feature is not there in CaRMetal.
 +
 +
=P th  term of an AP is Q and Q th term of an AP is P . Then find PQ th term ?=
 +
 +
'''Mallikarjun Sudi, Ghs Yelhari'''  All maths teachers pls solve this problem
 +
P th  term of an AP is Q and Q th term of an AP is P . Then find PQ th term ?
 +
 +
''' Sneha Titus, University Resource Centre, Azim Premji University'''
 +
This is a very nice problem. Here is the solution that I worked out.
 +
 +
 +
 +
Let the nth term be Tn = a + (n‒1)d, where a is the first term and d is the common difference.
 +
 +
Given: Tp = q = a + (p‒1)d
 +
 +
And    Tq = p = a + (q‒1)d
 +
 +
So Tp ‒Tq = q ‒ p  = a + (p‒1)d ‒[a + (q‒1)d]
 +
 +
                    q ‒ p  = pd ‒ d ‒ qd + d
 +
 +
                  q ‒ p  = (p ‒ q) d
 +
 +
∴ d = = ‒ 1
 +
 +
And  since  Tq = p = a + (q‒1)d,
 +
 +
                            p = a + (q ‒1)(‒1) = a ‒q + 1
 +
 +
                so that a = p + q ‒1
 +
 +
Now, Tpq = a + (pq‒1)d = a + (pq – 1)(‒1) = a ‒pq + 1 = p + q ‒1 ‒pq + 1 = p + q ‒pq
 +
 +
 +
 +
Example T2 = 4 and T4 = 2, what is T8
 +
 +
T2 = 4 = a + (2‒1)d = a + d
 +
 +
T4 = 2 = a + (4‒1)d = a + 3d
 +
 +
T2 ‒T4 = 4 ‒ 2  = a + d ‒[a + 3d] =  – 2d
 +
 +
              2 = ‒2d
 +
 +
∴ d = ‒1
 +
 +
And  T2 = 4 = a + (2‒1)(‒1) = a ‒1
 +
 +
∴ a = 4 + 1 = 5
 +
 +
And T8 = a + (8‒1)d] = a +7 d = a ‒ 7 = 5 ‒ 7 = ‒2
 +
 +
The A.P with a = 5, d = ‒1 is
 +
 +
5, 4, 3, 2, 1, 0, ‒1, ‒2,……….
 +
 +
Notice that T2 = 4 and T4 = 2 and T8 = ‒2
 +
    
= Which day is Pi Day ? =  
 
= Which day is Pi Day ? =  
283

edits

Navigation menu