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Mensuration
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Revision as of 11:38, 10 July 2014
149 bytes added
,
11:38, 10 July 2014
→solved problems on cone Example 10
Line 405:
Line 405:
knowledge to be used
knowledge to be used
−
#radius=
+
#radius=
diameter/2
−
+
#density=
mass/volume
−
#density=
# knowledge of measurements
# knowledge of measurements
#Formula of volume of cones
#Formula of volume of cones
Line 418:
Line 417:
#units conversion
#units conversion
−
solution:
+
solution:
<br>
−
d=14cm r
==
=7cm, h=51cm<br>
+
d=14cm r=7cm, h=51cm<br>
Volume of cone=
Volume of cone=
−
<math>\frac{1}{3}{Л}{r^2}h
+
=
<math>\frac{1}{3}{Л}{r^2}h<
/
math>
<br>
−
<math>
\frac{1}{3}{\frac{22}{7}}{7^2}51
−
−
To calculate weight of the solid cone we have to use density of the given material.
−
−
density=10gm/
−
=
Kg
/
+
=
<math>\frac{1}{3}{X}{\frac{22}{7}}{X}{7^2}{X}51<
/
math><br>
+
=<math>2618{cm^3}</math><br>
+
To calculate weight of the solid cone we have to use density of the given material.<br>
+
density=<math>10gm/{cm^3}</math><br>
+
=<math>{\frac{10Kg}{1000cm^3}}</math><br>
Weight of solid cone=volumeXdensity
Weight of solid cone=volumeXdensity
−
=
2618XKg
/
+
=
<math>2618{cm^3}{X}{\frac{10Kg}{1000cm^3}}<
/
math><br>
−
=26.18Kg
+
=26.18Kg
= Project Ideas =
= Project Ideas =
Saroja Adur
138
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