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From Karnataka Open Educational Resources
Activities-Pythagoras theorem problems (view source)
Revision as of 13:04, 11 July 2014
, 13:04, 11 July 2014no edit summary
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# The sides of a right angled triangle are in an AP. Show that sides are in ther ratio 3:4:5+
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OC= 3.25 mt
OC= 3.25 mt
radius of arch is 3.25 mt
radius of arch is 3.25 mt
+# 3 The sides of a right angled triangle are in an AP. Show that sides are in ther ratio 3:4:5
+'''Solution'''
−IN right angled triangle ABC
+If ∟B=90º and sides are in AP
+Let AB= a-d
+ BC= a
+ AC= a+d
+then <math>(a+d)^2=a^2+(a-d)^2</math>
+<math>a^2+d^2+2ad=a^2+a^2+d^2-2ad</math>
+<math>a^2=4ad</math>
+a=4d
+AB=a-d=4d-d=3d
+BC= a=4d
+AC= a+d+ 4d+d =5d
+ratio of sides is 3d:4d:5d
+if sides of the right angled triangle are in ratio 3:4:5 then their sides are in AP
