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Weight of solid cone=volumeXdensity
Weight of solid cone=volumeXdensity
=<math>2618{cm^3}{X}{\frac{10Kg}{1000cm^3}}</math><br>
=<math>2618{cm^3}{X}{\frac{10Kg}{1000cm^3}}</math><br>
−=26.18Kg
+=26.18Kg<br>
+====problem on combination of solids example 01====
+# Statement of the problem<br>
+#A Cylindrical container of radius 6cm and height 15cm is filled with ice cream. The whole ice cream has to be filled in 10 equal cones with hemispherical tops. and the height
+of the conical portion is 4 times the radius of its base.<br>.
+Assumptions
+#Student should know volume of cone,and volume of Hemisphere
+# Student should know the value of л=22/7
+# Student should know the difference between radius and height
+# Student should know the proper substitution simplification
+Concepts to be taught
+#Let us consider the volume of a cone having hemispherical top =2л
+#Volume of Cylindrical container is equated to volume of cone having hemispherical top
+Gaps
+# Comparision between the volumes of cylinder and (cone+Hemisphere)
+Skills
+# To imagine a cone , Hemisphere,and cylinder
+# To imagine a cone having Hemispherical top
+Algorthem<br>
+Part 1:<br> To derive the volume of a cone with hemispherical top<br>
+#volume of a cone with hemispherical top<br>=<math>{\frac{1}{3}}л{r^2}h+{\frac{2}{3}}л{r^3}</math><br>
+ =<math>{\frac{1}{3}}л4r +{\frac{2}{3}}л{r^3}</math>(on simplification)<br>
+ =<math>2л{r^3}</math><br>
+Part 2 :<br>To calculate the volume of 10 cone with hemispherical top<br>
+ =<math>10X2л{r^3}</math><br>
+ =<math>20л{r^3}</math><br>
+ To calculate the volume of ice-cream in cylindrical container<br>
+ =<math>л{r^2}h</math><br>
+ = л X6X6X15<br>
+ =540лc<br>
+Part 3 :<br>To apply condition given in the problem<br>
+ volume of 10 cone with hemispherical top= volume of cylindrical container<br>
+ <math>20л{r^3}</math> =540л<br>
+ <math>{r^3}</math>=<math>{\frac{540л}{20л}}</math><br>
+ =27<br>
+ r=3cm<br>
+Hence the radius of cream cones=3cm
+=
= Project Ideas =
= Project Ideas =