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Activities - progressions problems (view source)
Revision as of 15:41, 12 August 2014
, 15:41, 12 August 2014→Algorithm
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Line 124:
Here we cancel 'a' because it is in both side of the equal sign and after cancel 'a' we get,<br>
Here we cancel 'a' because it is in both side of the equal sign and after cancel 'a' we get,<br>
<math>\frac{2b} {a + b}</math> = <math>\frac{1} {5}</math><br>
<math>\frac{2b} {a + b}</math> = <math>\frac{1} {5}</math><br>
+Cross multiply we get,<br>
+a + b = 10b ----------------->2<br>
+Take '10b' to left hand side, we get<br>
+a + b – 10b = 0<br>
+a – 9b = 0<br>