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mLine 1:
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Line 143: − + − + − + − + − + − + + + + − + − + − + − + + + + − + − + − + − + + + + − + − + − + − + + + + + + + + + + + + + + − + − |n=50 − |Σfx=660 − + + + + + + + + + + + + + + + + + − Standard deviation σ=<math>\sqrt{\frac {\sum {fx^2}}{n}-({\frac{\sum fx}{n})^2}}</math> <br>+ − σ=<math>\sqrt{\frac{10700}{50}-({\frac{660}{50})^2}}</math> <br> − σ=<math>\sqrt{214-174.24}</math> <br> − σ=<math>\sqrt{39.96}</math> <br> − σ=6.3
Activity- statistics problems (view source)
Revision as of 09:56, 30 October 2019
, 09:56, 30 October 2019added Category:Statistics using HotCat
=Problem 1=
=Problem 1=
If n =10, = 12 and
If n =10, <math>\bar x </math> = 12 and<br>
<math>\sum{x^2}= 1530 find the standard deviation </math> <br>
<math>\sum{x^2}= 1530 find the standard deviation </math> <br>
=INTERPRETATION OF PROBLEM=
=INTERPRETATION OF PROBLEM=
|32
|32
|128
|128
|-2
| -2
|-8
| -8
|4
|4
|16
|16
|-
|-
|34-38
|34-38
|128
|7
|080
|36
|064
|252
|0640
| -1
| -7
|1
|7
|-
|-
|38-42
|38-42
|-2
|9
|195
|40
|169
|360
|2535
|0
|0
|0
|0
|-
|-
|42-46
|42-46
|10
|11
|180
|44
|324
|484
|3240
|1
|11
|1
|11
|-
|-
|46-50
|46-50
|08
|6
|184
|48
|529
|288
|4232
|2
|12
|4
|24
|-
|-
|50-54
|50-54
|3
|52
|156
|3
|9
|9
|27
|-
|
|
|n=40
|
|
|Σfx=1668
|
|
|
|Σfd=17
|
|
|Σfx²=10710
|Σfd²=85
|}
|}
A=assumed average.<br>
c=4<br>
d=<math>\frac{x-A}{c}</math>=<math>\frac{32-40}{4}</math>=<math>\frac{-8}{4}=-2</math><br>
assumed mean A=<math>\frac{\sum fx}{n}</math>=<math>\frac{1668}{40}=41.7</math><br>
Varience σ²=[<math>\frac{\sum {fd^2}}{n}-({\frac{\sum fx}{n})^2}]c^2</math> <br>
σ²=[<math>\frac{85}{40}-({\frac{17}{40})^2}]4^2</math> <br>
σ²=[2.125-0.180]16<br>
σ²=[1.945]16<br>
σ²=31.12<br>
standard deviation, σ=<math>\sqrt{varience}</math> <br>
σ=<math>\sqrt{31.12}</math> <br>
σ=5.58
[[Category:Statistics]]