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=8-3<br>=5<br>
=8-3<br>=5<br>
'''to back to concept page'''
'''to back to concept page'''
+[[http://karnatakaeducation.org.in/KOER/en/index.php/Quadratic_Equations#Hints_for_difficult_problems| quadratic equation problems]]<br>
+2.The altitude of a triangle is 6cm greter than its base. If its area is 108cmsq .Find its base.<br>
+[[solution]]<br>
+Statement: Solving problem based on quadratic equations.<br>
+[[solution]]
+*Interpretation of the problem:<br> * Converting data in to eqn.<br> *Knowledge about area of a triangle.<br>*knowledge of the formula of area of triangle.<br>*Methods of finding the roots of the eqn.<br> *Methods of finding the roots of the
+*Different approches to solve the problem: <br>*Factorisation
+*Using formula
+*using graph
+*Concept used:Forming the eqn. 216=x(x+6)
+216=x2+6x<br>
+x2 +6x -216=0<br>
+Substitution: x 2 +18x-12x -216=0<br>
+Simplification: x(x+18)-12(x+18)=0<br>
+(x+18)( x-12)=0<br>
+(x+18)=0 (x-12)=0<br>
+x=-18, x=12<br>.
+# Base=12cm, <br> Altitude=x+6
+
+=12+6=18cm.<br>
+'''Prior Knowledge''' -<br>
+*Methods of solving the Eqn<br>
+*Factorisation<br>
+*Using Formula<br>
+*Using Graph<br>
[[http://karnatakaeducation.org.in/KOER/en/index.php/Quadratic_Equations#Hints_for_difficult_problems| quadratic equation problems]]
[[http://karnatakaeducation.org.in/KOER/en/index.php/Quadratic_Equations#Hints_for_difficult_problems| quadratic equation problems]]