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Line 168: − Statement: Solving problem based on quadratic equations.<br> − [[solution]] − *Interpretation of the problem:<br> * Converting data in to eqn.<br> *Knowledge about area of a triangle.<br>*knowledge of the formula of area of triangle.<br>*Methods of finding the roots of the eqn.<br> *Methods of finding the roots of the − *Different approches to solve the problem: <br>*Factorisation − *Using formula − *using graph − *Concept used:Forming the eqn. 216=x(x+6) − 216=x2+6x<br> − x2 +6x -216=0<br> − Substitution: x 2 +18x-12x -216=0<br> − Simplification: x(x+18)-12(x+18)=0<br> − (x+18)( x-12)=0<br> − (x+18)=0 (x-12)=0<br> − x=-18, x=12<br>. − # Base=12cm, <br> Altitude=x+6 − − =12+6=18cm.<br> − '''Prior Knowledge''' -<br> − *Methods of solving the Eqn<br> − *Factorisation<br> − *Using Formula<br> − *Using Graph<br>
→Hints for difficult problems
2.The altitude of a triangle is 6cm greter than its base. If its area is 108cmsq .Find its base.<br>
2.The altitude of a triangle is 6cm greter than its base. If its area is 108cmsq .Find its base.<br>
[[solution]]<br>
[[solution]]<br>
=Ex.no.9.11 /problem no.9=
=Ex.no.9.11 /problem no.9=