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Parallelogram on same base and between same parallels have equal area (view source)
Revision as of 10:27, 5 September 2020
, 10:27, 5 September 2020no edit summary
=== Process (How to do the activity) ===
=== Process (How to do the activity) ===
{{Geogebra|kxre9cuf}}
{{Geogebra|kxre9cuf}}GEOMETRICAL VERIFICATION:
GIVEN :
AB ∥ FC and AB is the same base.
Parallelograms ABCD and ABEF are
on the same base AB and between
same parallels AB and FC.
PROOF :
Δ BCE ≅ Δ ADF (By SAS Congruence Criterion)
ar (BCE) = ar (ADF) = =
( Areas of Congruent figures are equal )
OBSERVATION / RESULT / OUTCOME :
Area of the parallelogram ABCD
= Area of the Trapezium ABED + Area of the Triangle BCE
ar (ABCD) = ar (BCE) + ar (ABED)
<nowiki>= + =</nowiki>
Area of the parallelogram ABEF
= Area of the Trapezium ABED + Area of the Triangle ADF
ar (ABEF) = ar (ABED) + ar (ADF)
<nowiki>= + =</nowiki>
Hence the theorem is verified.
=== Evaluation at the end of the activity ===
=== Evaluation at the end of the activity ===
Go back to the page - [[KVS Quadrilaterals|click here]]
Go back to the page - [[KVS Quadrilaterals|click here]]