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# How can you reason that the perpendicular bisector for any length of chord always passes through the centre of the circle.
 
# How can you reason that the perpendicular bisector for any length of chord always passes through the centre of the circle.
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===Activity No # ===
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===Activity No # 2.Theorem 2.Congruent chords are equidistant from the center of a circle. ===
 
{| style="height:10px; float:right; align:center;"
 
{| style="height:10px; float:right; align:center;"
 
|<div style="width:150px;border:none; border-radius:10px;box-shadow: 5px 5px 5px #888888; background:#f5f5f5; vertical-align:top; text-align:center; padding:5px;">
 
|<div style="width:150px;border:none; border-radius:10px;box-shadow: 5px 5px 5px #888888; background:#f5f5f5; vertical-align:top; text-align:center; padding:5px;">
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