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From Karnataka Open Educational Resources
Circles Tangents Problems (view source)
Revision as of 05:20, 14 August 2014
, 05:20, 14 August 2014→==
Let ∠QBP=x˚<br>
Let ∠QBP=x˚<br>
∴∠QPB=x˚ (∵PQ=BQ)<br>
∴∠QPB=x˚ (∵PQ=BQ)<br>
Now Let ∠PAQ=x˚<br>
Now Let ∠PAQ=x˚<br>
