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From Karnataka Open Educational Resources
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SO=OP=14 cm    <br>  hence Radius of given circle is 14 cm
 
SO=OP=14 cm    <br>  hence Radius of given circle is 14 cm
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=Problem 5=
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=Problem 5 [Ex-15.2-B8]=
 
A circle is touching the side BC of  △ABC at P. AB and AC when produced are touching the circle at Q and R respectively. Prove that AQ =<math>\frac{1}{2}</math> [perimeter of  △ABC].
 
A circle is touching the side BC of  △ABC at P. AB and AC when produced are touching the circle at Q and R respectively. Prove that AQ =<math>\frac{1}{2}</math> [perimeter of  △ABC].
 
[[File:123.png|300px]]
 
[[File:123.png|300px]]
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∴ AQ = <math>\frac{1}{2}</math> [perimeter of  △ABC]
 
∴ AQ = <math>\frac{1}{2}</math> [perimeter of  △ABC]
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=Problem-6 [Ex-15.4-B3]=
 
=Problem-6 [Ex-15.4-B3]=
 
In circle with center O , diameter AB and a chord AD are drawn. Another circle drawn with OA  as diameter to cut AD at C. Prove that BD=2OC.[[File:15.4B3.png|300px]]
 
In circle with center O , diameter AB and a chord AD are drawn. Another circle drawn with OA  as diameter to cut AD at C. Prove that BD=2OC.[[File:15.4B3.png|300px]]
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