Changes
From Karnataka Open Educational Resources
14 bytes added
, 15:38, 18 August 2014
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| SO=OP=14 cm <br> hence Radius of given circle is 14 cm | | SO=OP=14 cm <br> hence Radius of given circle is 14 cm |
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− | =Problem 5= | + | =Problem 5 [Ex-15.2-B8]= |
| A circle is touching the side BC of △ABC at P. AB and AC when produced are touching the circle at Q and R respectively. Prove that AQ =<math>\frac{1}{2}</math> [perimeter of △ABC]. | | A circle is touching the side BC of △ABC at P. AB and AC when produced are touching the circle at Q and R respectively. Prove that AQ =<math>\frac{1}{2}</math> [perimeter of △ABC]. |
| [[File:123.png|300px]] | | [[File:123.png|300px]] |
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| ∴ AQ = <math>\frac{1}{2}</math> [perimeter of △ABC] | | ∴ AQ = <math>\frac{1}{2}</math> [perimeter of △ABC] |
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| =Problem-6 [Ex-15.4-B3]= | | =Problem-6 [Ex-15.4-B3]= |
| In circle with center O , diameter AB and a chord AD are drawn. Another circle drawn with OA as diameter to cut AD at C. Prove that BD=2OC.[[File:15.4B3.png|300px]] | | In circle with center O , diameter AB and a chord AD are drawn. Another circle drawn with OA as diameter to cut AD at C. Prove that BD=2OC.[[File:15.4B3.png|300px]] |