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From Karnataka Open Educational Resources
784 bytes removed ,  17:20, 16 August 2014
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2.The altitude of a triangle is 6cm greter than its base. If its area is 108cmsq .Find its base.<br>
 
2.The altitude of a triangle is 6cm greter than its base. If its area is 108cmsq .Find its base.<br>
 
[[solution]]<br>
 
[[solution]]<br>
Statement: Solving problem based on quadratic equations.<br>
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[[solution]]
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*Interpretation  of the problem:<br> * Converting data in to eqn.<br> *Knowledge about area of a triangle.<br>*knowledge of the formula of area of triangle.<br>*Methods of finding the roots of the eqn.<br> *Methods of finding the roots of the
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*Different approches to solve the problem: <br>*Factorisation
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*Using formula
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*using graph
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*Concept used:Forming the eqn. 216=x(x+6)
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216=x2+6x<br>
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x2 +6x -216=0<br>
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Substitution:  x 2 +18x-12x -216=0<br>
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Simplification:  x(x+18)-12(x+18)=0<br>
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(x+18)( x-12)=0<br>
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(x+18)=0 (x-12)=0<br>
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x=-18, x=12<br>.
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# Base=12cm,  <br> Altitude=x+6
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=12+6=18cm.<br>
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'''Prior Knowledge''' -<br>
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*Methods of solving the Eqn<br>
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*Factorisation<br>
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*Using Formula<br>
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*Using Graph<br>
      
=Ex.no.9.11 /problem no.9=
 
=Ex.no.9.11 /problem no.9=
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