Changes
From Karnataka Open Educational Resources
28 bytes added
, 08:22, 10 July 2014
Line 419: |
Line 419: |
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| solution: | | solution: |
− | d=14cm r===7cm, h=51cm | + | d=14cm r===7cm, h=51cm<br> |
− | Volume of cone=Лh | + | Volume of cone= |
− | =XX7X7X51=2618
| + | <math>\frac{1}{3}{Л}{r^2}h |
| + | <math>\frac{1}{3}{\frac{22}{7}}{7^2}51 |
| + | |
| To calculate weight of the solid cone we have to use density of the given material. | | To calculate weight of the solid cone we have to use density of the given material. |
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