Changes
From Karnataka Open Educational Resources
149 bytes added
, 11:38, 10 July 2014
Line 405: |
Line 405: |
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| knowledge to be used | | knowledge to be used |
− | #radius= | + | #radius=diameter/2 |
− | | + | #density=mass/volume |
− | #density= | |
| # knowledge of measurements | | # knowledge of measurements |
| #Formula of volume of cones | | #Formula of volume of cones |
Line 418: |
Line 417: |
| #units conversion | | #units conversion |
| | | |
− | solution: | + | solution:<br> |
− | d=14cm r===7cm, h=51cm<br> | + | d=14cm r=7cm, h=51cm<br> |
| Volume of cone= | | Volume of cone= |
− | <math>\frac{1}{3}{Л}{r^2}h | + | =<math>\frac{1}{3}{Л}{r^2}h</math><br> |
− | <math>\frac{1}{3}{\frac{22}{7}}{7^2}51 | |
− | | |
− | To calculate weight of the solid cone we have to use density of the given material.
| |
− |
| |
− | density=10gm/
| |
| | | |
− | =Kg/
| + | =<math>\frac{1}{3}{X}{\frac{22}{7}}{X}{7^2}{X}51</math><br> |
| + | =<math>2618{cm^3}</math><br> |
| + | To calculate weight of the solid cone we have to use density of the given material.<br> |
| + | density=<math>10gm/{cm^3}</math><br> |
| + | =<math>{\frac{10Kg}{1000cm^3}}</math><br> |
| Weight of solid cone=volumeXdensity | | Weight of solid cone=volumeXdensity |
− | =2618XKg/
| + | =<math>2618{cm^3}{X}{\frac{10Kg}{1000cm^3}}</math><br> |
− | =26.18Kg
| + | =26.18Kg |
| | | |
| = Project Ideas = | | = Project Ideas = |