Changes
From Karnataka Open Educational Resources
784 bytes removed
, 22:50, 16 August 2014
| Line 168: |
Line 168: |
| | 2.The altitude of a triangle is 6cm greter than its base. If its area is 108cmsq .Find its base.<br> | | 2.The altitude of a triangle is 6cm greter than its base. If its area is 108cmsq .Find its base.<br> |
| | [[solution]]<br> | | [[solution]]<br> |
| − | Statement: Solving problem based on quadratic equations.<br>
| |
| − | [[solution]]
| |
| − | *Interpretation of the problem:<br> * Converting data in to eqn.<br> *Knowledge about area of a triangle.<br>*knowledge of the formula of area of triangle.<br>*Methods of finding the roots of the eqn.<br> *Methods of finding the roots of the
| |
| − | *Different approches to solve the problem: <br>*Factorisation
| |
| − | *Using formula
| |
| − | *using graph
| |
| − | *Concept used:Forming the eqn. 216=x(x+6)
| |
| − | 216=x2+6x<br>
| |
| − | x2 +6x -216=0<br>
| |
| − | Substitution: x 2 +18x-12x -216=0<br>
| |
| − | Simplification: x(x+18)-12(x+18)=0<br>
| |
| − | (x+18)( x-12)=0<br>
| |
| − | (x+18)=0 (x-12)=0<br>
| |
| − | x=-18, x=12<br>.
| |
| − | # Base=12cm, <br> Altitude=x+6
| |
| − |
| |
| − | =12+6=18cm.<br>
| |
| − | '''Prior Knowledge''' -<br>
| |
| − | *Methods of solving the Eqn<br>
| |
| − | *Factorisation<br>
| |
| − | *Using Formula<br>
| |
| − | *Using Graph<br>
| |
| | | | |
| | =Ex.no.9.11 /problem no.9= | | =Ex.no.9.11 /problem no.9= |
