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Activities-Pythagoras theorem problems (view source)
Revision as of 07:09, 11 July 2014
, 07:09, 11 July 2014no edit summary
#In Right angled ∆ABC,∟BAC= 90°,∟B: ∟C = 1:2 andAC= 4cm.calculate thelenght of BC
#1 In Right angled ∆ABC,∟BAC= 90°,∟B: ∟C = 1:2 andAC= 4cm.calculate thelenght of BC
''''''Solution'''''''''
''''''Solution'''''''''
in some special right angled triangle
in some special right angled triangle
BC = 8 cm
BC = 8 cm
#A door of width 6 mt has an archabove it having aheight of 2 mt , find the radius if the arch
#2 A door of width 6 mt has an archabove it having aheight of 2 mt , find the radius if the arch
Solution
In figure given
AB=6 mt width of door
CD=2 mt height of arch
let OC is radius of arch
OD= x mt
jion OB,
in ∆ODB ∟D= 90º
<math>OB^2=OD^2+DB^2</math>
<math>(x+2)^2=3^2+x^2</math>
<math>4+4x+9=9+x^2</math>
4x=9-4
x=<math>\frac{5}{4}</math>
x=1.25
But OC = 2+x
OC= 2+1.25
OC= 3.25 mt
radius of arch is 3.25 mt
# The sides of a right angled triangle are in an AP. Show that sides are in ther ratio 3:4:5
# The sides of a right angled triangle are in an AP. Show that sides are in ther ratio 3:4:5