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From Karnataka Open Educational Resources
1,209 bytes added ,  10:02, 5 November 2019
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====== [[Pi the mathematical constant|Pi the mathematical constant]] ======
 
====== [[Pi the mathematical constant|Pi the mathematical constant]] ======
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==== '''Learning Objective''' ====
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Show that the ratio of the circumference of a circle to its diameter is a constant value – Pi
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====Material and Resources Required====
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Projector, Pencil, Paper
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====Pre-requisites/Instructions====
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First for a circle of diameter 1 unit show the Geogebra file
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[[http://rmsa.karnatakaeducation.org.in/sites/rmsa.karnatakaeducation.org.in/files/documents/pi_1.html]]
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To demonstrate the value of Pi move the slider named a from minimum to maxiumum value and observe the circumference
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====Evaluation====
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Use the GeoGebra file [[http://rmsa.karnatakaeducation.org.in/sites/rmsa.karnatakaeducation.org.in/files/documents/Constant_Pi.html]] and illustrate and verify that the ratio is true for different radius by moving the radius slider and using the table below to compute the values.
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[[Image:KOER%20Circles_html_14d27306.png|650px|link=https://karnatakaeducation.org.in/KOER/en/index.php/File:KOER_Circles_html_14d27306.png]]
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[[Image:KOER%20Circles_html_7b6eda1c.png|650px|link=https://karnatakaeducation.org.in/KOER/en/index.php/File:KOER_Circles_html_7b6eda1c.png]]
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{| border="1"
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|-
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|Radius of circle r
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|Circumference of Circle C
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|C/2r
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|-
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|6
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|18.85
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|<nowiki>-</nowiki>
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|-
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|2.5
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|15.71
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|<nowiki>-</nowiki>
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|-
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|.........
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|<nowiki>-</nowiki>
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|<nowiki>-</nowiki>
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|}
 
=== Concept #2 Terms associated with circles ===
 
=== Concept #2 Terms associated with circles ===
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To construct Transverse common tangents to two circles.
 
To construct Transverse common tangents to two circles.
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[[Image:KOER%20Circles_html_m38f1dae5.png|link=https://karnatakaeducation.org.in/KOER/en/index.php/File:KOER_Circles_html_m38f1dae5.png]]
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[[Image:KOER%20Circles_html_m38f1dae5.png|link=]]
 
====Activity 1 Tangents====
 
====Activity 1 Tangents====
 
====Learning Objectives====
 
====Learning Objectives====