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Circles Tangents Problems (view source)

Revision as of 05:24, 14 August 2014

72 bytes added , 05:24, 14 August 2014

→‎Algorithm

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∴∠QPB=x˚ (∵PQ=BQ)<br>

∴∠QPB=x˚ (∵PQ=BQ)<br>

−

Now Let ∠PAQ=x˚<br>

+

Now Let ∠PAQ=Y˚<br>

+

∠QPA=Y˚ (∵ PQ=AQ)<br>

+

∴In △PAB<br>

+

+

∠PAB+∠PBA+∠APB=180˚

=problem 3 [Ex-15.2 B.7]=

=problem 3 [Ex-15.2 B.7]=

Naveena kumara A G

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