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∴ ∆AOP ≅ ∆BOP [SAS postulate]  <br>
 
∴ ∆AOP ≅ ∆BOP [SAS postulate]  <br>
 
∴  AP = BP [corresponding sides of congruent triangles ]
 
∴  AP = BP [corresponding sides of congruent triangles ]
 +
=problem 4 [Ex-15.2 B.8 ]
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