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From Karnataka Open Educational Resources
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∴ AQ = <math>\frac{1}{2}</math> [perimeter of  △ABC]
 
∴ AQ = <math>\frac{1}{2}</math> [perimeter of  △ABC]
=Probiem-6 [Ex-15.4-B3]=
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=Problem-6 [Ex-15.4-B3]=
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In circle with center O , diameter AB and a chord AD are drawn. Another circle drawn with OA  as diameter to cut AD at C. Prove that BD=2OC.[[File:15.4B3.png|300px]]
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