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474 bytes added ,  10:42, 12 November 2019
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_FORCETOC_
   
=Problem 1=
 
=Problem 1=
 
Exercise 16.1<br>Problem 7.
 
Exercise 16.1<br>Problem 7.
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=Problem 2=
 
=Problem 2=
 
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Solved problems on cone Example 1
===solved problems on cone Example 10===
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=<math>2618{cm^3}{X}{\frac{10Kg}{1000cm^3}}</math><br>
 
=<math>2618{cm^3}{X}{\frac{10Kg}{1000cm^3}}</math><br>
 
=26.18Kg<br>
 
=26.18Kg<br>
====problem on combination of solids example 01====
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Problem-03<br>
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=Problem 3=
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problem on combination of solids example 01
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#A Cylindrical container of radius 6cm and height 15cm is filled with ice cream. The whole ice cream has to be distributed to 10 children in equal cones with hemispherical tops. If the height  
 
#A Cylindrical container of radius 6cm and height 15cm is filled with ice cream. The whole ice cream has to be distributed to 10 children in equal cones with hemispherical tops. If the height  
 
of the conical portion is 4 times the radius of its base , find the radius of the cream cones.<br>
 
of the conical portion is 4 times the radius of its base , find the radius of the cream cones.<br>
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# To imagine a cone , Hemisphere,and cylinder
 
# To imagine a cone , Hemisphere,and cylinder
 
# To imagine a cone having Hemispherical top
 
# To imagine a cone having Hemispherical top
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r=3cm<br>
 
r=3cm<br>
 
Hence the radius of cream cones=3cm
 
Hence the radius of cream cones=3cm
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4)Frustum of Cone (Exercise 16.3 Problem 03)
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*A bucket in the shape of a frustum with the top and bottom circles of rarii 15cm and 10cm. Its depth  is 12cm. Find its curved surface area and total surface area.
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(Express the answer in terms of π)
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[[Image:frustum of cone.png|link=https://karnatakaeducation.org.in/KOER/en/index.php/File:Frustum_of_cone.png]]
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[http://karnatakaeducation.org.in/KOER/en/index.php?title=Mensuration#Hints_for_difficult_problems '''Solution''']
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[[Category:Mensuration]]

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