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OP=OQ ----  radii of the same circle
 
OP=OQ ----  radii of the same circle
 
OA is joined.<br>
 
OA is joined.<br>
In quadrillateral APOQ ,
+
In quadrillateral APOQ ,<br>
∠APO=∠AQO= [radius drawn at the point of contact is perpendicular to the tangent]
+
∠APO=∠AQO= [radius drawn at the point of contact is perpendicular to the tangent]<br>
∠PAQ+∠POQ=  
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∠PAQ+∠POQ=<br>
Or, ∠PAQ+∠POQ=  
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Or, ∠PAQ+∠POQ=<br>
∠PAQ = -∠POQ ----------1
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∠PAQ = -∠POQ ----------1<br>
Triangle POQ is isoscles. Therefore ∠OPQ=∠OQP
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Triangle POQ is isoscles. Therefore ∠OPQ=∠OQP<br>
∠POQ+∠OPQ+∠OQP=
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∠POQ+∠OPQ+∠OQP=<br>
Or  ∠POQ+2∠OPQ=
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Or  ∠POQ+2∠OPQ=<br>
2∠OPQ=- ∠POQ  ------2
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2∠OPQ=- ∠POQ  ------2<br>
From 1 and 2  
+
From 1 and 2 <br>
 
∠PAQ=2∠OPQ
 
∠PAQ=2∠OPQ
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