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Line 52: Line 52:  
b)<br>
 
b)<br>
 
Let ∠QBP=x˚<br>
 
Let ∠QBP=x˚<br>
∴∠QPB=x˚ (∵PQ=BQ)<br>
+
∴∠QPB=x˚             (∵PQ=BQ)<br>
 
Now Let ∠PAQ=x˚<br>
 
Now Let ∠PAQ=x˚<br>
  

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