Changes
From Karnataka Open Educational Resources
71 bytes added
, 10:47, 14 August 2014
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∴tangent at P bisects AB at Q.<br>
∴tangent at P bisects AB at Q.<br>
b)<br>
b)<br>
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Let ∠QBP=x˚<br>
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∴∠QPB=x˚ (∵PQ=BQ)<br>
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Now Let ∠PAQ=x˚<br>
=problem 3 [Ex-15.2 B.7]=
=problem 3 [Ex-15.2 B.7]=