Revision as of 23:03, 31 July 2014

Problem-1

prove that ${\frac {1-\tan ^{2}A}{1+\tan ^{2}A}}=1-\sin ^{2}A$

Develop the skill of proving problem based trigonometric identity

Problem solving

 When A=60°

LHS=Failed to parse (syntax error): {\displaystyle \frac{1-\tan^2 60°}{1+\tan^2 60°}}

@@ Line 15: / Line 15: @@
 ==Methos==
 # '''Generalisation By Verification'''
-   When A=30°
+   When A=60°
-LHS=<math>\frac{1-\tan^2 30°}{1+\tan^2 30°}</math> <br>
+LHS=<math>\frac{1-\tan^2 60°}{1+\tan^2 60°}</math> <br>
-   =<math>\frac{1-{\frac{1}\sqrt{3}}^2 }{1+{\frac{1}\sqrt{3}}^2}</math>