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Circles <math>C_{1}</math> and <math>C_{2}</math> touch internally at a point A and AB is a chord of the circle<math>C_{1}</math> intersecting <math>C_{2}</math> at P, Prove that AP= PB.<br>
Circles <math>C_{1}</math> and <math>C_{2}</math> touch internally at a point A and AB is a chord of the circle<math>C_{1}</math> intersecting <math>C_{2}</math> at P, Prove that AP= PB.<br>
[[Image:problem 3 on circle.png|300px]]
[[Image:problem 3 on circle.png|300px]]
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Concepts used
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1. The radii of a circle are equal
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2.Properties of isosceles triangle.
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3.SAS postulate
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4.Properties of congruent triangles.
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Prerequisite knowledge
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1. The radii of a circle are equal.
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2. In an isosceles triangle angles opposite to equal sides are equal.
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3.All the elements of congruent triangles are equal.